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Question Number 89735 by cindiaulia last updated on 19/Apr/20

Commented by jagoll last updated on 19/Apr/20

$$\mathrm{red}\mathrm{parabola}\mathrm{y}={\mathrm{x}}^2+2\mathrm{x}$$$$\mathrm{blue}\mathrm{parabola}\mathrm{y}=-{\mathrm{x}}^2+4$$$$\mathrm{shaded}\mathrm{area}:{\mathrm{x}}^2+2\mathrm{x}=-{\mathrm{x}}^2+4$$$${2\mathrm{x}}^2+2\mathrm{x}-4=0$$$$\mathrm{\Delta }=4-4.2.(-4)=36$$$$\mathrm{area}=\frac{\mathrm{\Delta }\sqrt{\mathrm{\Delta }}}{{6\mathrm{a}}^2}=\frac{36.6}{6.2^2}=9\mathrm{sq}\mathrm{unit}$$$$$$

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