Question and Answers Forum

All Questions      Topic List

Algebra Questions

Previous in All Question      Next in All Question      

Previous in Algebra      Next in Algebra      

Question Number 11672 by @ANTARES_VY last updated on 29/Mar/17

$$8{\mathbf{x}}^3-6\mathbf{x}+1=0$$$$\mathbf{Solves}...$$

Commented by mrW1 last updated on 29/Mar/17

$$seegeneralsolution:$$

Commented by mrW1 last updated on 29/Mar/17

Commented by @ANTARES_VY last updated on 30/Mar/17

$$\mathbf{which}\mathbf{program}\mathbf{told}$$

Answered by b.e.h.i.8.3.4.1.7@gmail.com last updated on 29/Mar/17

Answered by b.e.h.i.8.3.4.1.7@gmail.com last updated on 29/Mar/17

$$\mathrm{\Delta }=b^2-3ac=0-3\times 8\times (-6)=144⟩0$$$$k=\frac{-27a^{2}d}{2\sqrt{{\mathrm{\Delta }}^3}}=-0.5\Rightarrow \mid k\mid ⩽1$$$$x_1=\frac{2\sqrt{\mathrm{\Delta }.}cos\left(\frac{1}{3}{cos}^{-1}k\right)-b}{3a}\frac{}{}=$$$$x_1=\frac{-2\times 12cos\left(20\right)-0}{3\times 8}=\frac{24\times 0.9396}{24}=-0.9396$$$$x_2=\frac{-2\times 12cos(20-120)}{24}=0.1736$$$$x_3=\frac{-2\times 12cos(20+120)}{24}=0.7660$$

Commented by @ANTARES_VY last updated on 30/Mar/17

$$8{\mathbf{x}}^3-6\mathbf{x}+1=0\mathbf{this}\mathbf{development}$$$$\mathbf{is}\mathbf{an}\mathbf{example}?$$

Terms of Service

Privacy Policy

Contact: info@tinkutara.com