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Question Number 90178 by I want to learn more last updated on 21/Apr/20

Commented by I want to learn more last updated on 21/Apr/20

I got  26.6 degree, please help me check.

$$\mathrm{I}\:\mathrm{got}\:\:\mathrm{26}.\mathrm{6}\:\mathrm{degree},\:\mathrm{please}\:\mathrm{help}\:\mathrm{me}\:\mathrm{check}. \\ $$

Answered by TANMAY PANACEA. last updated on 21/Apr/20

tan30^o =((100−50)/(base))  base=50(√3)   tanθ=((100)/(50(√3)))=(2/(√3))  tanθ≈tan49^o   θ≈49^o

$${tan}\mathrm{30}^{{o}} =\frac{\mathrm{100}−\mathrm{50}}{{base}} \\ $$$${base}=\mathrm{50}\sqrt{\mathrm{3}}\: \\ $$$${tan}\theta=\frac{\mathrm{100}}{\mathrm{50}\sqrt{\mathrm{3}}}=\frac{\mathrm{2}}{\sqrt{\mathrm{3}}} \\ $$$${tan}\theta\approx{tan}\mathrm{49}^{{o}} \\ $$$$\theta\approx\mathrm{49}^{{o}} \\ $$

Commented by I want to learn more last updated on 21/Apr/20

Sir,  which angle should be bigger

$$\mathrm{Sir},\:\:\mathrm{which}\:\mathrm{angle}\:\mathrm{should}\:\mathrm{be}\:\mathrm{bigger} \\ $$

Commented by I want to learn more last updated on 21/Apr/20

Please sir, the diagram.

$$\mathrm{Please}\:\mathrm{sir},\:\mathrm{the}\:\mathrm{diagram}. \\ $$

Commented by TANMAY PANACEA. last updated on 21/Apr/20

Commented by TANMAY PANACEA. last updated on 21/Apr/20

pls recheck

$${pls}\:{recheck} \\ $$

Commented by I want to learn more last updated on 21/Apr/20

I draw the angle in a wrong way then.

$$\mathrm{I}\:\mathrm{draw}\:\mathrm{the}\:\mathrm{angle}\:\mathrm{in}\:\mathrm{a}\:\mathrm{wrong}\:\mathrm{way}\:\mathrm{then}. \\ $$

Commented by I want to learn more last updated on 21/Apr/20

Thanks sir, i appreciate.

$$\mathrm{Thanks}\:\mathrm{sir},\:\mathrm{i}\:\mathrm{appreciate}. \\ $$

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