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Question Number 90198 by M±th+et£s last updated on 21/Apr/20

$$\int sin\left(dx\right)$$

Commented by mr W last updated on 22/Apr/20

$${it}^{\prime }snotadefinedthing!$$

Commented by M±th+et£s last updated on 22/Apr/20

$$ithinksirtanmysolutioniscorrect$$

Commented by mr W last updated on 22/Apr/20

$$asisaidthingslike\int f\left(dx\right){don}^{\prime }t$$$$existbecausetheyarenotdefined.$$$$dxisnotavariableoravalue.$$$$\int f\left(x\right)dxisdefinedas:$$$$\int f\left(x\right)dx=F\left(x\right)\equiv \frac{dF\left(x\right)}{dx}=f\left(x\right)$$$$both\int anddxarejustsymbols.$$$$$$$$canyoutellwhat\int f\left(dx\right)means?$$

Answered by frc2crc last updated on 22/Apr/20

$$itx+C$$

Commented by M±th+et£s last updated on 22/Apr/20

$$yes$$

Answered by TANMAY PANACEA. last updated on 22/Apr/20

$$sin\left(dx\right)\approx dx$$$$\int dx$$$$=x+c$$$$$$$$$$

Answered by M±th+et£s last updated on 22/Apr/20

$$I=\int \underset{△x\to 0}{lim}sin(△x)$$$$=\int \underset{△x\to 0}{lim}\frac{sin(△x)}{△x}△x$$$$=\int \underset{△x\to 0}{lim}\frac{sin(△x)}{△x}\underset{△x\to 0}{lim}(△x)$$$$I=\int dx=x+c$$

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