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Question Number 90226 by manuel__ last updated on 22/Apr/20
limx→0(x3(ex−1)−x2xex−x)=?
Commented by john santu last updated on 22/Apr/20
limx→0x2(ex−1)−xex−1=limx→02x(ex−1)+x2ex−1ex=−1
Commented by mathmax by abdo last updated on 22/Apr/20
letf(x)=x3(ex−1)−x2xex−x⇒f(x)=x2(ex−1)−xex−1ex∼1+x⇒x2(ex−1)−x∼x3−x⇒f(x)∼x3−xx=x2−1⇒limx→0f(x)=−1
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