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Question Number 90282 by 20000193 last updated on 22/Apr/20

$$\frac{1}{2\alpha +\beta }+\frac{1}{\alpha +2\beta }$$

Commented by jagoll last updated on 22/Apr/20

$$\frac{\alpha +2\beta +2\alpha +\beta }{(2\alpha +\beta )(\alpha +2\beta )}=\frac{3\alpha +3\beta }{2{\alpha }^2+5\alpha \beta +2{\beta }^2}$$

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