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Question Number 90432 by jagoll last updated on 23/Apr/20

lim_(x→−∞)  x[(√(x^2 +1))−x ] =?

$$\underset{{x}\rightarrow−\infty} {\mathrm{lim}}\:\mathrm{x}\left[\sqrt{\mathrm{x}^{\mathrm{2}} +\mathrm{1}}−\mathrm{x}\:\right]\:=? \\ $$

Commented by mathmax by abdo last updated on 23/Apr/20

we have lim_(x→−∞)  x =−∞  and  lim_(x→−∞) (√(x^2 +1))−x =+∞ ⇒lim_(x→−∞) x((√(x^2 +1))−x) =−∞

$${we}\:{have}\:{lim}_{{x}\rightarrow−\infty} \:{x}\:=−\infty\:\:{and} \\ $$$${lim}_{{x}\rightarrow−\infty} \sqrt{{x}^{\mathrm{2}} +\mathrm{1}}−{x}\:=+\infty\:\Rightarrow{lim}_{{x}\rightarrow−\infty} {x}\left(\sqrt{{x}^{\mathrm{2}} +\mathrm{1}}−{x}\right)\:=−\infty \\ $$

Answered by jagoll last updated on 23/Apr/20

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