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Question Number 90531 by Mikael_786 last updated on 24/Apr/20

$$Pleasehelpmetofindthevalue$$$$of{}^{\prime }{n}^{\prime }$$$$C_8^{n+3}=C_{20}^{n+3}$$

Commented by mr W last updated on 24/Apr/20

$$n+3=8+20$$$$\Rightarrow n=25$$

Commented by jagoll last updated on 24/Apr/20

$$\frac{(n+3)!}{8!(n-5)!}=\frac{(n+3)!}{20!(n-17)!}$$$$8!(n-5)!=20!(n-17)!$$$$n=25$$

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