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Question Number 90628 by Josephbaraka@gmail.com last updated on 25/Apr/20
Thevalueofsinπ14sin3π14sin5π14is
Commented by jagoll last updated on 25/Apr/20
x=π14⇒7x=π2w=sinxsin3xsin5x2wcosx=sin2xsin5xsin3x4wcosx=(cos3x−cos7x)sin3x4wcosx=cos3xsin3x8wcosx=sin6xw=sin6x8cosx=cos(π14)cos(π14)=18sin6x=sin(3π7)=cos(π14)
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