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Question Number 90647 by I want to learn more last updated on 25/Apr/20

Commented by I want to learn more last updated on 25/Apr/20

For the string to be kept tight,  find the relationship between  x and y

$$\mathrm{For}\:\mathrm{the}\:\mathrm{string}\:\mathrm{to}\:\mathrm{be}\:\mathrm{kept}\:\mathrm{tight},\:\:\mathrm{find}\:\mathrm{the}\:\mathrm{relationship}\:\mathrm{between} \\ $$$$\mathrm{x}\:\mathrm{and}\:\mathrm{y} \\ $$

Commented by mr W last updated on 25/Apr/20

what do you mean with x and y?

$${what}\:{do}\:{you}\:{mean}\:{with}\:{x}\:{and}\:{y}? \\ $$

Commented by I want to learn more last updated on 25/Apr/20

Find x interms of y sir

$$\mathrm{Find}\:\mathrm{x}\:\mathrm{interms}\:\mathrm{of}\:\mathrm{y}\:\mathrm{sir} \\ $$

Commented by mr W last updated on 25/Apr/20

you didn′t answer my question:  what are x and y? names of the objects?  weight of them? speed of them?  acceleration of them?....

$${you}\:{didn}'{t}\:{answer}\:{my}\:{question}: \\ $$$${what}\:{are}\:{x}\:{and}\:{y}?\:{names}\:{of}\:{the}\:{objects}? \\ $$$${weight}\:{of}\:{them}?\:{speed}\:{of}\:{them}? \\ $$$${acceleration}\:{of}\:{them}?.... \\ $$

Commented by I want to learn more last updated on 25/Apr/20

Ohh, i get now,  A  and  B  are  loads  And a movable pulley with distance  x  and  y

$$\mathrm{Ohh},\:\mathrm{i}\:\mathrm{get}\:\mathrm{now}, \\ $$$$\mathrm{A}\:\:\mathrm{and}\:\:\mathrm{B}\:\:\mathrm{are}\:\:\mathrm{loads} \\ $$$$\mathrm{And}\:\mathrm{a}\:\mathrm{movable}\:\mathrm{pulley}\:\mathrm{with}\:\mathrm{distance}\:\:\mathrm{x}\:\:\mathrm{and}\:\:\mathrm{y} \\ $$

Commented by I want to learn more last updated on 25/Apr/20

distance  x  and  y  sir

$$\mathrm{distance}\:\:\mathrm{x}\:\:\mathrm{and}\:\:\mathrm{y}\:\:\mathrm{sir} \\ $$

Commented by mr W last updated on 25/Apr/20

2(dy/dt)=(dx/dt)  2dy=dx  2y+C=x

$$\mathrm{2}\frac{{dy}}{{dt}}=\frac{{dx}}{{dt}} \\ $$$$\mathrm{2}{dy}={dx} \\ $$$$\mathrm{2}{y}+{C}={x} \\ $$

Commented by I want to learn more last updated on 25/Apr/20

Ummm... Thanks sir

$$\mathrm{Ummm}...\:\mathrm{Thanks}\:\mathrm{sir} \\ $$

Commented by I want to learn more last updated on 25/Apr/20

Ummm... Thanks sir

$$\mathrm{Ummm}...\:\mathrm{Thanks}\:\mathrm{sir} \\ $$

Commented by I want to learn more last updated on 25/Apr/20

I appreciate your time sir.

$$\mathrm{I}\:\mathrm{appreciate}\:\mathrm{your}\:\mathrm{time}\:\mathrm{sir}. \\ $$

Commented by I want to learn more last updated on 25/Apr/20

Commented by I want to learn more last updated on 25/Apr/20

Sir,  please help with this last one, am using the two to solve  some questions.   The first one you solved have give me more idea to tackle  the questions here.

$$\mathrm{Sir},\:\:\mathrm{please}\:\mathrm{help}\:\mathrm{with}\:\mathrm{this}\:\mathrm{last}\:\mathrm{one},\:\mathrm{am}\:\mathrm{using}\:\mathrm{the}\:\mathrm{two}\:\mathrm{to}\:\mathrm{solve} \\ $$$$\mathrm{some}\:\mathrm{questions}.\: \\ $$$$\mathrm{The}\:\mathrm{first}\:\mathrm{one}\:\mathrm{you}\:\mathrm{solved}\:\mathrm{have}\:\mathrm{give}\:\mathrm{me}\:\mathrm{more}\:\mathrm{idea}\:\mathrm{to}\:\mathrm{tackle} \\ $$$$\mathrm{the}\:\mathrm{questions}\:\mathrm{here}. \\ $$

Commented by I want to learn more last updated on 25/Apr/20

from:   2y + C   =  x  Here, can i say     2y_1  − x_1   =  2y_2   −  x_2   =  C?

$$\mathrm{from}:\:\:\:\mathrm{2}\boldsymbol{\mathrm{y}}\:+\:\boldsymbol{\mathrm{C}}\:\:\:=\:\:\boldsymbol{\mathrm{x}} \\ $$$$\mathrm{Here},\:\mathrm{can}\:\mathrm{i}\:\mathrm{say} \\ $$$$\:\:\:\mathrm{2y}_{\mathrm{1}} \:−\:\mathrm{x}_{\mathrm{1}} \:\:=\:\:\mathrm{2y}_{\mathrm{2}} \:\:−\:\:\mathrm{x}_{\mathrm{2}} \:\:=\:\:\mathrm{C}? \\ $$

Commented by I want to learn more last updated on 25/Apr/20

Sir,    V_A   =  3    and   V_B   =  5

$$\mathrm{Sir},\:\:\:\:\mathrm{V}_{\mathrm{A}} \:\:=\:\:\mathrm{3}\:\:\:\:\mathrm{and}\:\:\:\mathrm{V}_{\mathrm{B}} \:\:=\:\:\mathrm{5} \\ $$

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