Question Number 90765 by john santu last updated on 26/Apr/20 | ||
$${if}\:\int\:\left(\mathrm{ln}\left({x}\right)\right)^{\mathrm{2}} {dx}\:=\: \\ $$$${x}\left(\:\mathrm{ln}^{\mathrm{2}} \left({x}\right)+{a}\:\mathrm{ln}\left({x}\right)+{b}\right)\:+{C} \\ $$$${a},{b}\:,\:{C}\:{are}\:{constant}.\: \\ $$$${find}\:{the}\:{value}\:{of}\:{a}\:{and}\:{b}\: \\ $$ | ||
Commented by jagoll last updated on 26/Apr/20 | ||
$$\int\:{f}\left({x}\right)\:{dx}\:=\:{h}\left({x}\right)\:\Rightarrow\:{f}\left({x}\right)\:=\:{h}'\left({x}\right) \\ $$$$\mathrm{ln}^{\mathrm{2}} \left({x}\right)\:=\:\mathrm{ln}^{\mathrm{2}} \left({x}\right)+{a}\:\mathrm{ln}\left({x}\right)+{b}\:+\: \\ $$$${x}\left(\:\frac{\mathrm{2ln}\left({x}\right)}{{x}}+\:\frac{{a}}{{x}}\right)\: \\ $$$$\mathrm{0}\:=\:\left({a}+\mathrm{2}\right)\mathrm{ln}\left({x}\right)\:+\:\left({a}+{b}\right)\: \\ $$$$\begin{cases}{{a}\:=\:−\mathrm{2}}\\{{b}\:=\:\mathrm{2}\:}\end{cases} \\ $$ | ||
Commented by john santu last updated on 26/Apr/20 | ||
$${good} \\ $$ | ||