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Question Number 9096 by tawakalitu last updated on 17/Nov/16

Answered by mrW last updated on 19/Nov/16

let R_1 and R_2 be the rent of the first and second house last year. (R_1 /R_2 )=((16)/(23)) R_1 =((16)/(23))R_2 ((1.25R_1 )/(R_2 +5200))=(9/(11)) 1.25×11R_1 =9R_2 +9×5200 1.25×11×((16)/(23))R_2 =9R_2 +9×5200 (1.25×11×((16)/(23))−9)R_2 =9×5200 R_2 =((23)/(13))×9×5200=82800 $ R_1 =((16)/(23))×82800=57600 $

$${let}\:{R}_{\mathrm{1}} \:{and}\:{R}_{\mathrm{2}} \:{be}\:{the}\:{rent}\:{of}\:{the}\:{first} \\ $$$${and}\:{second}\:{house}\:{last}\:{year}. \\ $$$$\frac{{R}_{\mathrm{1}} }{{R}_{\mathrm{2}} }=\frac{\mathrm{16}}{\mathrm{23}} \\ $$$${R}_{\mathrm{1}} =\frac{\mathrm{16}}{\mathrm{23}}{R}_{\mathrm{2}} \\ $$$$\frac{\mathrm{1}.\mathrm{25}{R}_{\mathrm{1}} }{{R}_{\mathrm{2}} +\mathrm{5200}}=\frac{\mathrm{9}}{\mathrm{11}} \\ $$$$\mathrm{1}.\mathrm{25}×\mathrm{11}{R}_{\mathrm{1}} =\mathrm{9}{R}_{\mathrm{2}} +\mathrm{9}×\mathrm{5200} \\ $$$$\mathrm{1}.\mathrm{25}×\mathrm{11}×\frac{\mathrm{16}}{\mathrm{23}}{R}_{\mathrm{2}} =\mathrm{9}{R}_{\mathrm{2}} +\mathrm{9}×\mathrm{5200} \\ $$$$\left(\mathrm{1}.\mathrm{25}×\mathrm{11}×\frac{\mathrm{16}}{\mathrm{23}}−\mathrm{9}\right){R}_{\mathrm{2}} =\mathrm{9}×\mathrm{5200} \\ $$$${R}_{\mathrm{2}} =\frac{\mathrm{23}}{\mathrm{13}}×\mathrm{9}×\mathrm{5200}=\mathrm{82800}\:\$ \\ $$$${R}_{\mathrm{1}} =\frac{\mathrm{16}}{\mathrm{23}}×\mathrm{82800}=\mathrm{57600}\:\$ \\ $$

Commented by tawakalitu last updated on 19/Nov/16

Thanks so much sir. i really appreciate.

$$\mathrm{Thanks}\:\mathrm{so}\:\mathrm{much}\:\mathrm{sir}.\:\mathrm{i}\:\mathrm{really}\:\mathrm{appreciate}. \\ $$

Commented by tawakalitu last updated on 19/Nov/16

God bless you.

$$\mathrm{God}\:\mathrm{bless}\:\mathrm{you}. \\ $$

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