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Question Number 91166 by student work last updated on 28/Apr/20

Commented by Prithwish Sen 1 last updated on 28/Apr/20

$$\mathrm{the}\mathrm{curves}$$$$\mathbf{y}={\mathbf{x}}^2\mathbf{and}\mathbf{y}={\mathbf{e}}^{\mathbf{x}}\mathrm{can}\mathrm{meet}\mathrm{at}\mathrm{atmost}\mathrm{two}\mathrm{points}\stackrel{}{.}$$

Commented by jagoll last updated on 28/Apr/20

$$usingLambertWfunction$$

Commented by 675480065 last updated on 28/Apr/20

$$\mathrm{true}$$$$\mathrm{but}\mathrm{can}\mathrm{newton}\mathrm{raphson}\mathrm{not}\mathrm{work}$$

Commented by mr W last updated on 28/Apr/20

$$itasksonlythenumberofsolutions,$$$$notthesolutionsself.$$

Commented by Prithwish Sen 1 last updated on 28/Apr/20

$$\mathbf{x}\backsimeq -0.7034(\mathbf{approx}.)$$

Commented by mr W last updated on 28/Apr/20

$$thereisonlyonesolutionwhichis$$$$x=-2\mathbb{W}\left(\frac{1}{2}\right)\approx -0.7034$$

Commented by MJS last updated on 28/Apr/20

$${\mathrm{there}}^{\prime }\mathrm{s}\mathrm{no}\mathrm{other}\mathrm{solution}\in \mathbb{C}$$

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