Question and Answers Forum

All Questions      Topic List

Algebra Questions

Previous in All Question      Next in All Question      

Previous in Algebra      Next in Algebra      

Question Number 91277 by john santu last updated on 29/Apr/20

p=1−(1/2)+(1/3)−(1/4)+...+(1/(2003))−(1/(2004))  q=(1/(1003))+(1/(1004))+...+(1/(2004))  p^2 +q^2  =

$${p}=\mathrm{1}−\frac{\mathrm{1}}{\mathrm{2}}+\frac{\mathrm{1}}{\mathrm{3}}−\frac{\mathrm{1}}{\mathrm{4}}+...+\frac{\mathrm{1}}{\mathrm{2003}}−\frac{\mathrm{1}}{\mathrm{2004}} \\ $$$${q}=\frac{\mathrm{1}}{\mathrm{1003}}+\frac{\mathrm{1}}{\mathrm{1004}}+...+\frac{\mathrm{1}}{\mathrm{2004}} \\ $$$${p}^{\mathrm{2}} +{q}^{\mathrm{2}} \:=\: \\ $$

Answered by naka3546 last updated on 30/Apr/20

Commented by jagoll last updated on 30/Apr/20

i think it wrong answer

$${i}\:{think}\:{it}\:{wrong}\:{answer} \\ $$

Commented by naka3546 last updated on 30/Apr/20

Show  your  workings, please

$${Show}\:\:{your}\:\:{workings},\:{please}\: \\ $$

Answered by naka3546 last updated on 30/Apr/20

Terms of Service

Privacy Policy

Contact: info@tinkutara.com