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Question Number 91298 by jagoll last updated on 29/Apr/20

$$whatistheparticularintegral$$$$of(D^2+6D+5)y=e^{-5x}$$

Commented by john santu last updated on 29/Apr/20

Answered by niroj last updated on 29/Apr/20

$$\mathrm{PI}=\frac{{\mathrm{e}}^{-5\mathrm{x}}}{{\mathrm{D}}^2+6\mathrm{D}+5}=\frac{\mathrm{x}}{2\mathrm{D}+6}{\mathrm{e}}^{-5\mathrm{x}}$$$$=\frac{\mathrm{x}.{\mathrm{e}}^{-5\mathrm{x}}}{-10+6}=-\frac{{\mathrm{xe}}^{-5\mathrm{x}}}{4}//.$$

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