How many eleven digits palindrome numbers can be formed by 0, 2, 3, 4, and 8 ? Zero in the middle of order always .


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Question Number 91336 by naka3546 last updated on 30/Apr/20

$H o w m a n y e l e v e n d i g i t s p a l i n d r o m e n u m b e r s c a n b e$ $f o r m e d b y 0, 2, 3, 4, a n d 8 ?$ $Z e r o i n t h e m i d d l e o f o r d e r a l w a y s .$
Commented by jagoll last updated on 30/Apr/20

$4! = 24$
Commented by naka3546 last updated on 30/Apr/20

$e l e v e n d i g i t s ?$
Commented by jagoll last updated on 30/Apr/20

$p o l y n d r o m e e l e v e n d i g i t$ $a b c d e d c b a$
Commented by jagoll last updated on 30/Apr/20

$a b c d 0 d c b a$ $a b c d = 4! = 24$
Commented by naka3546 last updated on 30/Apr/20

$n i n e d i g i t s {t h a t}^{'} s$
Commented by jagoll last updated on 30/Apr/20

$y e s$
Commented by jagoll last updated on 30/Apr/20

Commented by naka3546 last updated on 30/Apr/20

$22222022222$ $24222022242$ $24822022842$ $⋮$ $C a n b e o r d e r e d l i k e t h a t ?$
Commented by jagoll last updated on 30/Apr/20

$d o e s m e a n y o u r q u e s t i o n n o t$ $c l e a r . t h e r e i s n o e x p l a n a t i o n$ $t h a t t h e n u m b e r m a y r e p e a t!$
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