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Question Number 91353 by jagoll last updated on 30/Apr/20
dydx=e3x−y2
Answered by niroj last updated on 30/Apr/20
dydx=e3x.e−y21e−y2dy=e3xdx∫ey2dy...=∫e3xdx......π2errorf(iy)=e3x3+C
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