Question and Answers Forum

All Questions      Topic List

None Questions

Previous in All Question      Next in All Question      

Previous in None      Next in None      

Question Number 91497 by kikomssn@gmail.com last updated on 01/May/20

v=π∫_0 ^2 x^2 dx

v=π02x2dx

Commented by jagoll last updated on 01/May/20

= ((πx^3 )/3) ]_0 ^2  = ((8π)/3)

=πx33]02=8π3

Terms of Service

Privacy Policy

Contact: info@tinkutara.com