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Question Number 91500 by kikomssn@gmail.com last updated on 01/May/20

$$v=\pi {\int }_1^4[{(\frac{1}{4}.x^2)}^{2}dx$$

Commented by john santu last updated on 01/May/20

$$=\frac{\pi }{16}\times \frac{1}{5}\times (4^5-1)$$$$=\frac{1023\pi }{80}$$

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