Question Number 91688 by s.ayeni14@yahoo.com last updated on 02/May/20
$${solve}\:{equations}\:{x}^{{x}\:} +\:{y}^{{y}} \:=\:\mathrm{31}\:{and}\:{x}\:+\:{y}\:=\:\mathrm{5} \\ $$
Commented by mr W last updated on 02/May/20
$${i}\:{think}\:{you}\:{know}\:{by}\:{yourself}\:{x}=\mathrm{2},\:{y}=\mathrm{3} \\ $$$${since}\:\mathrm{2}^{\mathrm{2}} +\mathrm{3}^{\mathrm{3}} =\mathrm{4}+\mathrm{27}=\mathrm{31}. \\ $$$${if}\:{you}\:{ask}\:{if}\:{there}\:{is}\:{a}\:{method}\:{to} \\ $$$$``{calculate}''\:{the}\:{result},\:{the}\:{answer}\:{is} \\ $$$$``{no}''. \\ $$
Commented by jagoll last updated on 02/May/20
$${x}=\mathrm{2}\:,\:{y}\:=\:\mathrm{3}\: \\ $$$$\mathrm{2}^{\mathrm{2}} +\mathrm{3}^{\mathrm{3}} \:=\:\mathrm{4}+\mathrm{27}\:=\:\mathrm{31}\: \\ $$$$\mathrm{2}+\mathrm{3}\:=\:\mathrm{5}\: \\ $$