Question and Answers Forum

All Questions      Topic List

Others Questions

Previous in All Question      Next in All Question      

Previous in Others      Next in Others      

Question Number 91785 by zainal tanjung last updated on 03/May/20

given  these bellow sequenses .   find fifth term    1).  (1/5), (1/4) , (3/(11)), (2/7),...  2).  (3/5), ((−9)/(11)) , ((−25)/(19)), ((57)/(35)),...  3).   (1/6), (7/(11)) , ((13)/(16)), ((19)/(21)),...  4).   4,− (2/3) , −(4/(13)),− (1/5),...  5).  2, 9 , 28 , 65,...

$$\mathrm{given}\:\:\mathrm{these}\:\mathrm{bellow}\:\mathrm{sequenses}\:.\: \\ $$$$\mathrm{find}\:\mathrm{fifth}\:\mathrm{term} \\ $$$$ \\ $$$$\left.\mathrm{1}\right).\:\:\frac{\mathrm{1}}{\mathrm{5}},\:\frac{\mathrm{1}}{\mathrm{4}}\:,\:\frac{\mathrm{3}}{\mathrm{11}},\:\frac{\mathrm{2}}{\mathrm{7}},... \\ $$$$\left.\mathrm{2}\right).\:\:\frac{\mathrm{3}}{\mathrm{5}},\:\frac{−\mathrm{9}}{\mathrm{11}}\:,\:\frac{−\mathrm{25}}{\mathrm{19}},\:\frac{\mathrm{57}}{\mathrm{35}},... \\ $$$$\left.\mathrm{3}\right).\:\:\:\frac{\mathrm{1}}{\mathrm{6}},\:\frac{\mathrm{7}}{\mathrm{11}}\:,\:\frac{\mathrm{13}}{\mathrm{16}},\:\frac{\mathrm{19}}{\mathrm{21}},... \\ $$$$\left.\mathrm{4}\right).\:\:\:\mathrm{4},−\:\frac{\mathrm{2}}{\mathrm{3}}\:,\:−\frac{\mathrm{4}}{\mathrm{13}},−\:\frac{\mathrm{1}}{\mathrm{5}},... \\ $$$$\left.\mathrm{5}\right).\:\:\mathrm{2},\:\mathrm{9}\:,\:\mathrm{28}\:,\:\mathrm{65},... \\ $$

Commented by Tony Lin last updated on 03/May/20

1)(1/5),(2/8),(3/(11)),(4/(14)),(5/(17))

$$\left.\mathrm{1}\right)\frac{\mathrm{1}}{\mathrm{5}},\frac{\mathrm{2}}{\mathrm{8}},\frac{\mathrm{3}}{\mathrm{11}},\frac{\mathrm{4}}{\mathrm{14}},\frac{\mathrm{5}}{\mathrm{17}} \\ $$

Commented by Tony Lin last updated on 03/May/20

3)(1/6),(7/(11)),((13)/(16)),((19)/(21)),((25)/(26))

$$\left.\mathrm{3}\right)\frac{\mathrm{1}}{\mathrm{6}},\frac{\mathrm{7}}{\mathrm{11}},\frac{\mathrm{13}}{\mathrm{16}},\frac{\mathrm{19}}{\mathrm{21}},\frac{\mathrm{25}}{\mathrm{26}} \\ $$

Commented by Tony Lin last updated on 03/May/20

5)1^3 +1, 2^3 +1, 3^3 +1 , 4^3 +1 , 5^3 +1=126

$$\left.\mathrm{5}\right)\mathrm{1}^{\mathrm{3}} +\mathrm{1},\:\mathrm{2}^{\mathrm{3}} +\mathrm{1},\:\mathrm{3}^{\mathrm{3}} +\mathrm{1}\:,\:\mathrm{4}^{\mathrm{3}} +\mathrm{1}\:,\:\mathrm{5}^{\mathrm{3}} +\mathrm{1}=\mathrm{126} \\ $$

Commented by zainal tanjung last updated on 03/May/20

thank you sir

$$\mathrm{thank}\:\mathrm{you}\:\mathrm{sir} \\ $$

Commented by zainal tanjung last updated on 03/May/20

thank you sir

$$\mathrm{thank}\:\mathrm{you}\:\mathrm{sir} \\ $$

Terms of Service

Privacy Policy

Contact: info@tinkutara.com