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Question Number 91897 by john santu last updated on 03/May/20
limx→0sin(2x−sinx)1−1−x2=?
Commented by john santu last updated on 03/May/20
limx→02x−sinx1−(1−x22)=limx→02x−(x−x36)x22=limx→02(x+x36)x2=limx→02x+x3=DNE
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