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Question Number 92079 by mathmax by abdo last updated on 04/May/20

$$find{lim}_{x\to 0}\frac{e^{{sin}^{2}x}-e^{x^3-2x}}{x^2}$$

Commented by john santu last updated on 05/May/20

$$\underset{x\to 0}{\lim }\frac{\sin 2x{e}^{\sin {}^{2}x}-(3x^2-2)e^{x^3-2x}}{2x}$$$$\underset{x\to 0}{\lim }{e}^{\sin {}^{2}x}\left(\frac{\sin 2x}{2x}\right)-\underset{x\to 0}{\lim }{e}^{x^3-2x}\left(\frac{3x^2-2}{2x}\right)$$$$D\mathrm{NE}$$

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