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Question Number 92135 by jagoll last updated on 05/May/20

a^x  = log _a  (x)  a=?

$${a}^{{x}} \:=\:\mathrm{log}\:_{{a}} \:\left({x}\right) \\ $$$${a}=? \\ $$

Commented by Tony Lin last updated on 05/May/20

when 0<x<e^(−e) , x has three solutions  when e^(−e) ≤a<1, x has one solution  when 1<a< e^(1/e) , x has two solutions  when a=e^(1/e) , x has one solution  when a>e^(1/e) , x has no solutions  ∴ when a^x =log_a x  ⇒aε(0,e^(1/e) ]\{1}

$${when}\:\mathrm{0}<{x}<{e}^{−{e}} ,\:{x}\:{has}\:{three}\:{solutions} \\ $$$${when}\:{e}^{−{e}} \leqslant{a}<\mathrm{1},\:{x}\:{has}\:{one}\:{solution} \\ $$$${when}\:\mathrm{1}<{a}<\:{e}^{\frac{\mathrm{1}}{{e}}} ,\:{x}\:{has}\:{two}\:{solutions} \\ $$$${when}\:{a}={e}^{\frac{\mathrm{1}}{{e}}} ,\:{x}\:{has}\:{one}\:{solution} \\ $$$${when}\:{a}>{e}^{\frac{\mathrm{1}}{{e}}} ,\:{x}\:{has}\:{no}\:{solutions} \\ $$$$\therefore\:{when}\:{a}^{{x}} ={log}_{{a}} {x} \\ $$$$\Rightarrow{a}\epsilon\left(\mathrm{0},{e}^{\frac{\mathrm{1}}{{e}}} \right]\backslash\left\{\mathrm{1}\right\} \\ $$

Commented by mr W last updated on 05/May/20

a=1 ⇒one solution x=1

$${a}=\mathrm{1}\:\Rightarrow{one}\:{solution}\:{x}=\mathrm{1} \\ $$

Commented by jagoll last updated on 05/May/20

log _1 (1) defined?

$$\mathrm{log}\:_{\mathrm{1}} \left(\mathrm{1}\right)\:\mathrm{defined}? \\ $$

Commented by MJS last updated on 05/May/20

lim_(x→1)   log_x  x =lim_(x→1)  ((ln x)/(ln x)) =lim_(x→1)  1 =1  also log_0  0 =1  log_z  z =1 ∀z∈C

$$\underset{{x}\rightarrow\mathrm{1}} {\mathrm{lim}}\:\:\mathrm{log}_{{x}} \:{x}\:=\underset{{x}\rightarrow\mathrm{1}} {\mathrm{lim}}\:\frac{\mathrm{ln}\:{x}}{\mathrm{ln}\:{x}}\:=\underset{{x}\rightarrow\mathrm{1}} {\mathrm{lim}}\:\mathrm{1}\:=\mathrm{1} \\ $$$$\mathrm{also}\:\mathrm{log}_{\mathrm{0}} \:\mathrm{0}\:=\mathrm{1} \\ $$$$\mathrm{log}_{{z}} \:{z}\:=\mathrm{1}\:\forall{z}\in\mathbb{C} \\ $$

Commented by Tony Lin last updated on 05/May/20

a^a^x  =x  a^x lna=lnx  (xlna)e^(xlna) =xlnx  xlna=W(xlnx)  a=e^((W(xlnx))/x)

$${a}^{{a}^{{x}} } ={x} \\ $$$${a}^{{x}} {lna}={lnx} \\ $$$$\left({xlna}\right){e}^{{xlna}} ={xlnx} \\ $$$${xlna}=\mathbb{W}\left({xlnx}\right) \\ $$$${a}={e}^{\frac{\mathbb{W}\left({xlnx}\right)}{{x}}} \\ $$

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