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Question Number 92219 by ajfour last updated on 05/May/20

Commented by ajfour last updated on 05/May/20

If the red curve has equation  y=x^2 −bx+c=0  ∀  b, c >0 , then  find equation of upper cubic  in the form y=px^3 +qx+r.  Hence find (q/p), (r/p) .  Thus we can determine the  common root by using just  tbe Cardano formula.  hence all the roots of the red  cubic curve even when the  discriminant:   (c^2 /4)−(b^3 /(27)) < 0 .

$${If}\:{the}\:{red}\:{curve}\:{has}\:{equation} \\ $$$${y}={x}^{\mathrm{2}} −{bx}+{c}=\mathrm{0}\:\:\forall\:\:{b},\:{c}\:>\mathrm{0}\:,\:{then} \\ $$$${find}\:{equation}\:{of}\:{upper}\:{cubic} \\ $$$${in}\:{the}\:{form}\:{y}={px}^{\mathrm{3}} +{qx}+{r}. \\ $$$${Hence}\:{find}\:\frac{{q}}{{p}},\:\frac{{r}}{{p}}\:. \\ $$$${Thus}\:{we}\:{can}\:{determine}\:{the} \\ $$$${common}\:{root}\:{by}\:{using}\:{just} \\ $$$${tbe}\:{Cardano}\:{formula}. \\ $$$${hence}\:{all}\:{the}\:{roots}\:{of}\:{the}\:{red} \\ $$$${cubic}\:{curve}\:{even}\:{when}\:{the} \\ $$$${discriminant}:\:\:\:\frac{{c}^{\mathrm{2}} }{\mathrm{4}}−\frac{{b}^{\mathrm{3}} }{\mathrm{27}}\:<\:\mathrm{0}\:. \\ $$

Commented by ajfour last updated on 05/May/20

(without the use of trigonometric  solution of a cubic equation)

$$\left({without}\:{the}\:{use}\:{of}\:{trigonometric}\right. \\ $$$$\left.{solution}\:{of}\:{a}\:{cubic}\:{equation}\right) \\ $$

Commented by ajfour last updated on 05/May/20

but no, this again fails..!

$${but}\:{no},\:{this}\:{again}\:{fails}..! \\ $$

Commented by MJS last updated on 05/May/20

anyway, the black curve is not unique

$$\mathrm{anyway},\:\mathrm{the}\:\mathrm{black}\:\mathrm{curve}\:\mathrm{is}\:\mathrm{not}\:\mathrm{unique} \\ $$

Commented by ajfour last updated on 06/May/20

(q/p) and (r/p)  are unique, Sir!

$$\frac{{q}}{{p}}\:{and}\:\frac{{r}}{{p}}\:\:{are}\:{unique},\:{Sir}! \\ $$

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