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Question Number 923 by 123456 last updated on 25/Apr/15

f(x,y,z)=x+y+z g(x,y,z)=(x,y,z) h(x,y,z)=g(x,y,z)−▽f(x,y,z)=??? ▽∙h(x,y,z)=? ▽×h(x,y,z)=???

f(x,y,z)=x+y+zg(x,y,z)=(x,y,z)h(x,y,z)=g(x,y,z)−▽f(x,y,z)=???▽⋅h(x,y,z)=?▽×h(x,y,z)=???

Answered by 2closedStringsMeet last updated on 15/Aug/15

h=(x,y,z)−(1,1,1) ∴ ▽f=(1+0+0, 0+1+0, 0+0+1) ▽∙h=3 ∴ h=(x−1, y−1, z−1) ▽×h= (0,0,0)

h=(x,y,z)−(1,1,1)∴▽f=(1+0+0,0+1+0,0+0+1)▽⋅h=3∴h=(x−1,y−1,z−1)▽×h=(0,0,0)

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