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Question Number 92425 by Jidda28 last updated on 06/May/20

$$\mathrm{If}\mathrm{A}\mathrm{and}\mathrm{B}\mathrm{are}\mathrm{two}$$$$\mathrm{different}\mathrm{number}\mathrm{such}\mathrm{that}$$$$\mathrm{A}+\mathrm{B}=\mathrm{C}\mathrm{and}\mathrm{A}\times \mathrm{B}=\mathrm{C}$$$$\mathrm{find}\mathrm{A}\mathrm{and}\mathrm{B}.$$

Commented by mr W last updated on 06/May/20

$$A\ne B$$$$A+B=A\times B$$$$thereareinfinitesuchnumbers:$$$$foreachA\ne 0,\ne ,\ne 2thereisaB:$$$$B=\frac{A}{A-1}$$

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