Question and Answers Forum

All Questions      Topic List

Geometry Questions

Previous in All Question      Next in All Question      

Previous in Geometry      Next in Geometry      

Question Number 92518 by I want to learn more last updated on 07/May/20

Answered by mr W last updated on 07/May/20

Commented by mr W last updated on 07/May/20

EC=1−tan 25  FC=1−tan 20  tan ∠FEC=((FC)/(EC))=((1−tan 20)/(1−tan 25))  x=180−65−tan^(−1) ((1−tan 20)/(1−tan 25))=65°

EC=1tan25FC=1tan20tanFEC=FCEC=1tan201tan25x=18065tan11tan201tan25=65°

Commented by I want to learn more last updated on 07/May/20

Thanks sir. I really appreciate

Thankssir.Ireallyappreciate

Terms of Service

Privacy Policy

Contact: info@tinkutara.com