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Question Number 92807 by Crabby89p13 last updated on 09/May/20

Commented by i jagooll last updated on 09/May/20

$$28{\mathrm{cm}}^2$$

Answered by  M±th+et+s last updated on 09/May/20

Answered by  M±th+et+s last updated on 09/May/20

$$x+Z+Z+R+R+y=32+20+16$$$$x+y+2Z+2R=68$$$$x+y=68-2(Z-R)$$$$=68-\left(2\times 20\right)=28{cm}^2$$$$$$

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