Question Number 92997 by naka3546 last updated on 10/May/20
Answered by mr W last updated on 10/May/20
![say area of parallelogram is S [AED]+[CEB]=(S/2) [AED]=(S/2)−4321 [ADC]=(S/2)=[AED]+[CED]+[CEA] (S/2)=(S/2)−4321+1234+[CEA] ⇒[CEA]=4321−1234=3087](Q93009.png)
$${say}\:{area}\:{of}\:{parallelogram}\:{is}\:{S} \\ $$$$\left[{AED}\right]+\left[{CEB}\right]=\frac{{S}}{\mathrm{2}} \\ $$$$\left[{AED}\right]=\frac{{S}}{\mathrm{2}}−\mathrm{4321} \\ $$$$\left[{ADC}\right]=\frac{{S}}{\mathrm{2}}=\left[{AED}\right]+\left[{CED}\right]+\left[{CEA}\right] \\ $$$$\frac{{S}}{\mathrm{2}}=\frac{{S}}{\mathrm{2}}−\mathrm{4321}+\mathrm{1234}+\left[{CEA}\right] \\ $$$$\Rightarrow\left[{CEA}\right]=\mathrm{4321}−\mathrm{1234}=\mathrm{3087} \\ $$