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Question Number 93057 by gonzo last updated on 10/May/20
y=b1x1+b2x2+cineedtoarrangetheequationforthdvalueofx2
Commented by gonzo last updated on 10/May/20
ihavediscalculaandithelpsmeworkktthrough
Answered by prakash jain last updated on 10/May/20
y=b1x1+b2x2+csubtractb1x1+cfrombothsides.y−b1x1−c=b1x1+b2x2+c−b1x1−cy−b1x1−c=b2x2dividebyb2y−b1x1−cb2=b2x2b(x2=y−b1x1−cb2
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