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Question Number 93081 by Ar Brandon last updated on 10/May/20

Solve x^y =y^x    x, y ∈ N

$$\mathrm{Solve}\:\mathrm{x}^{\mathrm{y}} =\mathrm{y}^{\mathrm{x}} \:\:\:\mathrm{x},\:\mathrm{y}\:\in\:\mathbb{N} \\ $$

Commented by mr W last updated on 10/May/20

x=y=n∈N  or  x=2,y=4  or  x=4,y=2

$${x}={y}={n}\in\mathbb{N} \\ $$$${or} \\ $$$${x}=\mathrm{2},{y}=\mathrm{4} \\ $$$${or} \\ $$$${x}=\mathrm{4},{y}=\mathrm{2} \\ $$

Commented by Ar Brandon last updated on 10/May/20

thanks Sir, Good Evening

Commented by Rio Michael last updated on 10/May/20

okay sir, but i really don′t understand this method.

$$\mathrm{okay}\:\mathrm{sir},\:\mathrm{but}\:\mathrm{i}\:\mathrm{really}\:\mathrm{don}'\mathrm{t}\:\mathrm{understand}\:\mathrm{this}\:\mathrm{method}. \\ $$

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