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Question Number 93081 by Ar Brandon last updated on 10/May/20

$$\mathrm{Solve}{\mathrm{x}}^{\mathrm{y}}={\mathrm{y}}^{\mathrm{x}}\mathrm{x},\mathrm{y}\in \mathbb{N}$$

Commented by mr W last updated on 10/May/20

$$x=y=n\in \mathbb{N}$$$$or$$$$x=2,y=4$$$$or$$$$x=4,y=2$$

Commented by Ar Brandon last updated on 10/May/20

thanks Sir, Good Evening

Commented by Rio Michael last updated on 10/May/20

$$\mathrm{okay}\mathrm{sir},\mathrm{but}\mathrm{i}\mathrm{really}{\mathrm{don}}^{\prime }\mathrm{t}\mathrm{understand}\mathrm{this}\mathrm{method}.$$

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