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Question Number 93129 by 16091019 last updated on 11/May/20

$$derive{x}^2-(\alpha +\beta )x+\alpha \beta$$

Commented by 16091019 last updated on 11/May/20

Commented by i jagooll last updated on 11/May/20

$$(\mathrm{x}-\alpha )(\mathrm{x}-\beta )$$$$\mathrm{done}$$

Answered by Rio Michael last updated on 11/May/20

$$\mathrm{any}\mathrm{quadratic}\mathrm{with}\mathrm{roots}\alpha \mathrm{and}\beta$$$$\mathrm{is}\mathrm{of}\mathrm{the}\mathrm{form}(x-\alpha )(x-\beta )=0$$$$\Rightarrow x^2-(\alpha +\beta )x+\alpha \beta =0\mathrm{done}!$$

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