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Question Number 93366 by Rio Michael last updated on 12/May/20

 solve the equation   (z−2)^3  = (1/2)−i((√3)/2)

$$\:\mathrm{solve}\:\mathrm{the}\:\mathrm{equation} \\ $$$$\:\left({z}−\mathrm{2}\right)^{\mathrm{3}} \:=\:\frac{\mathrm{1}}{\mathrm{2}}−{i}\frac{\sqrt{\mathrm{3}}}{\mathrm{2}} \\ $$

Answered by prakash jain last updated on 12/May/20

(1/2)−i((√3)/2)  =e^(−iπ/3)   z−2=e^(−iπ/9)   z=2+cos ((π/9))−isin ((π/9))

$$\frac{\mathrm{1}}{\mathrm{2}}−{i}\frac{\sqrt{\mathrm{3}}}{\mathrm{2}} \\ $$$$={e}^{−{i}\pi/\mathrm{3}} \\ $$$${z}−\mathrm{2}={e}^{−{i}\pi/\mathrm{9}} \\ $$$${z}=\mathrm{2}+\mathrm{cos}\:\left(\frac{\pi}{\mathrm{9}}\right)−{i}\mathrm{sin}\:\left(\frac{\pi}{\mathrm{9}}\right) \\ $$

Commented by Rio Michael last updated on 12/May/20

thanks sir

$$\mathrm{thanks}\:\mathrm{sir} \\ $$

Commented by Rio Michael last updated on 13/May/20

sir please help me with Q93367

$$\mathrm{sir}\:\mathrm{please}\:\mathrm{help}\:\mathrm{me}\:\mathrm{with}\:\mathrm{Q93367} \\ $$

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