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Question Number 93428 by mhmd last updated on 13/May/20

Answered by john santu last updated on 13/May/20

$$10-\mathrm{x}=2\mid \mathrm{x}\mid \Rightarrow 100-20\mathrm{x}+{\mathrm{x}}^2={4\mathrm{x}}^2$$$${3\mathrm{x}}^2+20\mathrm{x}-100=0$$$$(3\mathrm{x}-10)(\mathrm{x}+10)=0$$$$\{\begin{array}{l}\mathrm{x}=\frac{10}{3}\Rightarrow \mathrm{y}=\frac{20}{3}\\ \mathrm{x}=-10\Rightarrow \mathrm{y}=20\end{array}$$$$$$

Commented by i jagooll last updated on 13/May/20

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Commented by mhmd last updated on 13/May/20

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