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Question Number 93530 by Shakhzod last updated on 13/May/20

(4x^2 +xy+y^2 )dx+(4y^2 +3xy+x^2 )dy=0

$$\left(\mathrm{4}{x}^{\mathrm{2}} +{xy}+{y}^{\mathrm{2}} \right){dx}+\left(\mathrm{4}{y}^{\mathrm{2}} +\mathrm{3}{xy}+{x}^{\mathrm{2}} \right){dy}=\mathrm{0} \\ $$

Commented by Shakhzod last updated on 13/May/20

Sorry.))

$$\left.{S}\left.{orry}.\right)\right) \\ $$$$ \\ $$$$ \\ $$

Commented by Shakhzod last updated on 13/May/20

That′s fixed it.

$${That}'{s}\:{fixed}\:{it}. \\ $$

Commented by Shakhzod last updated on 13/May/20

Did you see?

$${Did}\:{you}\:{see}? \\ $$

Commented by mr W last updated on 13/May/20

now you can solve it with y=xu.

$${now}\:{you}\:{can}\:{solve}\:{it}\:{with}\:{y}={xu}. \\ $$

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