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Question Number 93567 by oustmuchiya@gmail.com last updated on 13/May/20
GiventhatA={0,1,3,5}B={1,2,4,7}andC={1,2,3,5,8}provethat(i)(A∩B)∩C=A∩(B∩C)(ii)(A∪B)∪C=A∪(B∪C)(iii)(A∪B)∩C=(A∪C)∪(B∩C)(iv)(A∩C)∪B=(A∪B)∩(C∪B)
Commented by Ritu Jain last updated on 13/May/20
(i)(A∩B)∩C=A∩(B∩C)(A∩B)={0,1,3,5}∩{1,2,3,7}={1}LHS=(A∩B)∩C=({1})∩{1,2,3,5,8}={1}B∩C={1,2,4,7}∩{1,2,3,5,8}={1}RHS=A∩(B∩C)={0,1,3,5}∩({1}={1}LHS=RHS
Answered by otchereabdullai@gmail.com last updated on 14/May/20
ii.(AUB)={0,1,2,3,4,5,7}C={1,2,3,5,8}∴{AUB}UC={0,1,2,3,4,5,7,8}AlsoA={0,1,3,5}{BUC}={1,2,3,4,5,7,8}∴AU(BUC)={0,1,2,3,4,5,7,8}Nowsince(AUB)UC=AU(BUC)={0,1,2,3,4,5,7,8}wecanconcludethat(AUB)UC=AU(BUC).iii.(AUB)∩C=(AUC)U(B∩C)(AUB)={0,1,2,3,4,5,7}C={1,2,3,5,8}∴(AUB)∩C={0,1,2,3,4,5,7}∩{1,2,3,5,8}={1,2,3,5}also(AUC)={0,1,2,3,5,8}(B∩C)={1,2}∴(AUC)U(B∩C)={0,1,2,3,5,8}⇒(AUB)∩C≠(AUC)U(B∩C)
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