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Question Number 93683 by i jagooll last updated on 14/May/20

$$\int ({\mathrm{t}}^2\mathbf{i}+\cos 2\mathrm{t}\mathbf{j}+{\mathrm{e}}^{-\mathrm{t}}\mathbf{k})\mathrm{dt}$$

Answered by john santu last updated on 14/May/20

$$=\frac{1}{3}{\mathrm{t}}^3\overrightarrow{\mathrm{i}}+\frac{1}{2}\sin 2\mathrm{t}\overrightarrow{\mathrm{j}}-{\mathrm{e}}^{-\mathrm{t}}\overrightarrow{\mathrm{k}}+\mathrm{c}$$

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