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Question Number 93687 by Ayod 19 last updated on 14/May/20

If a and b are roots of the eqn   x^(2 ) +x=1111111122222222  Find the value of a−b.

$$\mathrm{If}\:{a}\:\mathrm{and}\:{b}\:\mathrm{are}\:\mathrm{roots}\:\mathrm{of}\:\mathrm{the}\:\mathrm{eqn} \\ $$$$\:\mathrm{x}^{\mathrm{2}\:} +\mathrm{x}=\mathrm{1111111122222222} \\ $$$$\mathrm{Find}\:\mathrm{the}\:\mathrm{value}\:\mathrm{of}\:{a}−{b}. \\ $$

Commented by Kunal12588 last updated on 14/May/20

(a+b)=−1  ab=−1111111122222222  a−b=(√((a+b)^2 −4ab))  you can find now

$$\left({a}+{b}\right)=−\mathrm{1} \\ $$$${ab}=−\mathrm{1111111122222222} \\ $$$${a}−{b}=\sqrt{\left({a}+{b}\right)^{\mathrm{2}} −\mathrm{4}{ab}} \\ $$$${you}\:{can}\:{find}\:{now} \\ $$

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