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Question Number 93762 by ckkim89 last updated on 14/May/20

	Answered by maths mind last updated on 14/May/20

	$= \frac{4 {x e}^{2 x}}{4 {(1 + 2 x)}^{2}} = \frac{1}{4} . \frac{{d e}^{2 x} . (1 + 2 x) - d (1 + 2 x) . e^{2 x}}{{(1 + 2 x)}^{2}}$ $\Rightarrow \int \frac{{x e}^{2 x}}{{(1 + 2 x)}^{2}} d x = \frac{1}{4} \int d (\frac{e^{2 x}}{1 + 2 x}) = \frac{1}{4} . \frac{e^{2 x}}{1 + 2 x} + c$
	Commented by ckkim89 last updated on 14/May/20
	It's awsome!!! Thanks!!
	Commented by M±th+et+s last updated on 15/May/20

	$n i c e t o s e e y o u a g a i n s i r$
	Commented by maths mind last updated on 18/May/20

	$i w i l l b a c k s o o n h o p e s o$ $i / w o r c k v e r r y h a r d t h e s e d a y s t o o b u s y$
	Commented by M±th+et+s last updated on 18/May/20

	$g o d b l e s s y o u r w o r k s i r$
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