Question Number 93940 by seedhamaieng@gmail.com last updated on 16/May/20 | ||
Commented by Tony Lin last updated on 16/May/20 | ||
$${cos}^{−\mathrm{1}} \frac{\mathrm{4}}{\mathrm{5}}={tan}^{−\mathrm{1}} \frac{\mathrm{3}}{\mathrm{4}} \\ $$$${tan}^{−\mathrm{1}} \frac{\mathrm{3}}{\mathrm{4}}+{tan}^{−\mathrm{1}} \frac{\mathrm{2}}{\mathrm{5}} \\ $$$$={tan}^{−\mathrm{1}} \frac{\frac{\mathrm{3}}{\mathrm{4}}+\frac{\mathrm{2}}{\mathrm{5}}}{\mathrm{1}−\frac{\mathrm{3}}{\mathrm{4}}×\frac{\mathrm{2}}{\mathrm{5}}} \\ $$$$={tan}^{−\mathrm{1}} \frac{\mathrm{23}}{\mathrm{14}} \\ $$ | ||
Commented by seedhamaieng@gmail.com last updated on 16/May/20 | ||
thanks sir | ||