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Question Number 93986 by $@ty@m123 last updated on 16/May/20

Answered by mr W last updated on 16/May/20

Commented by mr W last updated on 16/May/20

$$\left[AEF\right]=\frac{3}{5}\left[ABF\right]=\frac{3}{5}\times \frac{1}{6}\left[ABC\right]$$$$\left[BED\right]=\frac{2}{5}\left[BAD\right]=\frac{2}{5}\times \frac{4}{7}\left[ABC\right]$$$$\left[EFCD\right]=\left[ABC\right]-\left[AEF\right]-\left[BED\right]$$$$=(1-\frac{3}{5}\times \frac{1}{6}-\frac{2}{5}\times \frac{4}{7})\left[ABC\right]$$$$=\frac{47}{70}\left[ABC\right]$$$$\Rightarrow \frac{\left[EFCD\right]}{\left[ABC\right]}=\frac{47}{70}$$

Commented by $@ty@m123 last updated on 17/May/20

$$Thanksalot.$$

Answered by $@ty@m123 last updated on 17/May/20

Commented by $@ty@m123 last updated on 17/May/20

Got an alternative solution from my friend.

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