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Question Number 9399 by tawakalitu last updated on 04/Dec/16

Find the root of  bx^3  − (3b − 2)x^2  − 2(5b − 3)x + 20 = 0

$$\mathrm{Find}\:\mathrm{the}\:\mathrm{root}\:\mathrm{of} \\ $$$$\mathrm{bx}^{\mathrm{3}} \:−\:\left(\mathrm{3b}\:−\:\mathrm{2}\right)\mathrm{x}^{\mathrm{2}} \:−\:\mathrm{2}\left(\mathrm{5b}\:−\:\mathrm{3}\right)\mathrm{x}\:+\:\mathrm{20}\:=\:\mathrm{0} \\ $$

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