Question Number 9404 by alfat123 last updated on 05/Dec/16
Answered by geovane10math last updated on 06/Dec/16
$$\mathrm{I}\:\mathrm{can}'\mathrm{t}\:\mathrm{read}... \\ $$$${f}'\left({x}\right)\:=\:\mathrm{2}{x}\:+\:\mathrm{2} \\ $$$$\int{f}'\left({x}\right)\:{dx}\:=\:\int\:\mathrm{2}{x}\:+\:\mathrm{2}\:{dx}\:=\:\int\mathrm{2}{x}\:{dx}\:+\:\int\mathrm{2}\:{dx} \\ $$$$=\:{x}^{\mathrm{2}} \:+\:\mathrm{2}{x}\:+\:{C} \\ $$$${f}\left({x}\right)\:=\:{x}^{\mathrm{2}} \:+\:\mathrm{2}{x}\:+\:{C} \\ $$$${f}\left(\mathrm{2}\right)\:=\:\mathrm{8}\:+\:{C} \\ $$