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Question Number 94158 by seedhamaieng@gmail.com last updated on 17/May/20

Commented by prakash jain last updated on 17/May/20

$$\mathrm{mass}m$$$$\mathrm{acceleration}a=-\frac{R}{m}$$$$-veacclerarionasmentionin$$$$question$$$$\mathrm{using}\mathrm{relation}{v}^2-u^2=2as$$$$v^2-u^2=\left(2\right)(-\frac{R}{m})s$$$$\Rightarrow \frac{1}{2}m(u^2-v^2)=Rs$$

Commented by i jagooll last updated on 17/May/20

$$\mathrm{very}\mathrm{small}...$$

Commented by seedhamaieng@gmail.com last updated on 17/May/20

thanks sir

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