Question and Answers Forum

All Questions      Topic List

Geometry Questions

Previous in All Question      Next in All Question      

Previous in Geometry      Next in Geometry      

Question Number 94291 by I want to learn more last updated on 17/May/20

Commented by PRITHWISH SEN 2 last updated on 18/May/20

$$\mathrm{diagonal}=\sqrt{{(14+9)}^2+7^2}=17\sqrt{2}$$$$\therefore \mathbf{x}=17$$

Commented by I want to learn more last updated on 18/May/20

$$\mathrm{Thanks}\mathrm{sir}$$

Answered by Ar Brandon last updated on 18/May/20

$$\mathrm{H}=\sqrt{{(14+9)}^2+7^2}=17\sqrt{2}$$$${\mathrm{H}}^2={\mathrm{x}}^2+{\mathrm{x}}^2\Rightarrow \mathrm{x}=\sqrt{\frac{{\mathrm{H}}^2}{2}}=17\mathrm{cm}$$

Commented by I want to learn more last updated on 18/May/20

$$\mathrm{Thanks}\mathrm{sir}$$

Terms of Service

Privacy Policy

Contact: info@tinkutara.com