Question Number 94360 by Ahad last updated on 18/May/20
Commented by i jagooll last updated on 18/May/20
$$\mathrm{what}\:\mathrm{do}\:\mathrm{you}\:\mathrm{ask}\:? \\ $$
Commented by mr W last updated on 18/May/20
$${i}\:{don}'{t}\:{think}\:{the}\:{questioner}\:{is}\:{serious}. \\ $$$${why}\:\frac{\sqrt{{a}^{\mathrm{2}} +\mathrm{2}}}{\sqrt{{a}^{\mathrm{2}} +\mathrm{2}}},\:{not}\:{directly}\:\mathrm{1}? \\ $$
Commented by i jagooll last updated on 18/May/20
maybe just a test using this application
Answered by mathmax by abdo last updated on 18/May/20
$$\mathrm{i}\:\mathrm{think}\:\mathrm{the}\:\mathrm{question}\:\mathrm{is}\:\mathrm{simlify}\:\frac{\sqrt{\mathrm{a}^{\mathrm{2}} +\mathrm{2}}}{\sqrt{\mathrm{a}^{\mathrm{2}} −\mathrm{2}}}+\frac{\sqrt{\mathrm{a}^{\mathrm{2}} −\mathrm{2}}}{\sqrt{\mathrm{a}^{\mathrm{2}} +\mathrm{2}}} \\ $$$$\mathrm{A}\:=\frac{\left(\mathrm{a}^{\mathrm{2}} \:+\mathrm{2}\right)+\left(\mathrm{a}^{\mathrm{2}} −\mathrm{2}\right)}{\sqrt{\mathrm{a}^{\mathrm{4}} −\mathrm{4}}}\:=\frac{\mathrm{2a}^{\mathrm{2}} }{\sqrt{\mathrm{a}^{\mathrm{4}} −\mathrm{4}}} \\ $$