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Question Number 94360 by Ahad last updated on 18/May/20

Commented by i jagooll last updated on 18/May/20

$$\mathrm{what}\mathrm{do}\mathrm{you}\mathrm{ask}?$$

Commented by mr W last updated on 18/May/20

$$i{don}^{\prime }tthinkthequestionerisserious.$$$$why\frac{\sqrt{a^2+2}}{\sqrt{a^2+2}},notdirectly1?$$

Commented by i jagooll last updated on 18/May/20

maybe just a test using this application

Answered by mathmax by abdo last updated on 18/May/20

$$\mathrm{i}\mathrm{think}\mathrm{the}\mathrm{question}\mathrm{is}\mathrm{simlify}\frac{\sqrt{{\mathrm{a}}^2+2}}{\sqrt{{\mathrm{a}}^2-2}}+\frac{\sqrt{{\mathrm{a}}^2-2}}{\sqrt{{\mathrm{a}}^2+2}}$$$$\mathrm{A}=\frac{({\mathrm{a}}^2+2)+({\mathrm{a}}^2-2)}{\sqrt{{\mathrm{a}}^4-4}}=\frac{{2\mathrm{a}}^2}{\sqrt{{\mathrm{a}}^4-4}}$$

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