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Question Number 94406 by Power last updated on 18/May/20

Commented by Tony Lin last updated on 18/May/20

$$\underset{n=0}{\sum ^{\mathrm{\infty }}}\frac{x^n}{n!}=e^x$$$$\underset{n=0}{\sum ^{\mathrm{\infty }}}\frac{3^n}{n!}=e^3$$

Commented by Power last updated on 18/May/20

$$\mathrm{sir}\mathrm{prove}\mathrm{that}\mathrm{please}$$

Commented by prakash jain last updated on 18/May/20

$$e^x=\underset{n=0}{\sum ^{\mathrm{\infty }}}\frac{x^n}{n!}$$$$\mathrm{puy}x=3\mathrm{and}\mathrm{you}\mathrm{will}\mathrm{get}\mathrm{answer}.$$

Commented by prakash jain last updated on 18/May/20

$$\mathrm{proof}\mathrm{for}{e}^x\mathrm{series}?$$

Commented by MAB last updated on 18/May/20

$${it}^{\prime }sthetaylorseriesfor{e}^{x}at0$$

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