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Question Number 94424 by Abdulrahman last updated on 18/May/20

$$\mathrm{y}={\mathrm{x}}^{\mathrm{x}}$$$${\mathrm{y}}^{{}^{\prime }}=?$$

Commented by Tony Lin last updated on 18/May/20

$$y^{{}^{\prime }}=e^{xlnx}(lnx+1)$$$$=x^x(lnx+1)$$

Commented by PRITHWISH SEN 2 last updated on 18/May/20

$${\mathrm{y}}^{{}^{\prime }}={\mathrm{x}}^{\mathrm{x}}(\mathrm{lnx}+1)$$

Commented by Abdulrahman last updated on 18/May/20

$$\mathrm{thanks}$$

Commented by Abdulrahman last updated on 18/May/20

$$\mathrm{thankx}$$

Answered by prakash jain last updated on 18/May/20

$$\ln y=x\ln x$$$$\frac{1}{y}{y}^{\prime }=\ln x+x\times \frac{1}{x}=1+\ln x)$$$$y^{\prime }=y(1+\ln x)=x^x(1+\ln x)$$

Commented by Abdulrahman last updated on 18/May/20

$$\mathrm{thanks}$$

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