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Question Number 94510 by i jagooll last updated on 19/May/20

∫ ((√(tan x))/(sin x.cos x))dx

tanxsinx.cosxdx

Commented by PRITHWISH SEN 2 last updated on 19/May/20

∫((sec^2 x.(√(tanx)))/(tan x)) dx  now put tanx=t^2   ∫2dt=2(√)tanx+C  yes sir I fix it.Thamk you

sec2x.tanxtanxdxnowputtanx=t22dt=2tanx+CyessirIfixit.Thamkyou

Commented by john santu last updated on 19/May/20

∫ 2dt = 2t + c = 2(√(tan x)) + c

2dt=2t+c=2tanx+c

Commented by i jagooll last updated on 19/May/20

typo sir Pritwish  2(√(tan x)) + c

typosirPritwish2tanx+c

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